Google Interview Experience-1

Google Interview Experience - Bangalore

It was a nice experience to be part of google placement programme. There were 4 Rounds
The online test consists of 4 modules.

For each module, a timer is set (at the right-hand side bottom of the screen).

Total time given is 40 minutes.

Module 1: English (duration 5 min):

It consists of a single passage followed by 5 questions.

Module 2: General aptitude (duration 10 min):

Module 3: Technical questions (duration 15 min):

It consists of 15 questions where some are web based, HTML, protocols Etc. For this section going through COMPUTER NETWORKS subject will be helpful to a great extent.

Module 4: Test on Analysis (duration 10 min):

This section is the most time consuming one. Here we are asked to Rate certain sites along with an explanation. The images of these sites are also provided to us for a clear view and better understanding.
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Google Interview Experience - Hyderabad, April 22, 2016

Hi All,

I recently went to the interview for a Data Analyst position in Google.

The total experience was quite tough as it took me 3 days to complete the interview process.

In total, there were 4 rounds.

1 Round: Jam Session- Given a topic to speak about my role model and PI.

2 Round: Aptitude Round (Logical reasoning, Verbal and Non-Verbal, and Arithmetic).

3 Round: Client Round (Complete written test questions based on Non-Verbal and Personality Questions).

4 Round: HR round- It was completely based on how we introduce our self in front of HR.

First the HR asked about PI and some technical questions based on Puzzles, and simple series questions. HR gave me two puzzles to solve, I was done with only one puzzle the second was quite tough so I couldn't answer it.

So after the completion of 4 rounds, I thought that my HR was quite average. But after two days I got a call from the HR team and got the feedback that I have been selected for Google.

It was a huge dream for me to work in Google company. It took me 2 years to crack this job. So I would suggest all you guys that " always keep your hopes alive because miracles do happen in life".
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Google Interview Experience - Hyderabad

Hi Friends,

The online test consists of 4 modules. For each module a timer is set (at the right hand side bottom of the screen). Total time given is 40 minutes.

Module 1: English (duration 5 min):

It consists of a single passage followed by 5 questions.

Module 2: General aptitude (duration 10 min):

It consists of 6 questions based on simple logics.

For Eg:

1) 'Z' was invited by his brother 'A' to attend his daughter 'B's birthday party who was busy dancing with her brother 'C'. What is 'Z' to 'C'?

a) Uncle.
b) Nephew.
c) Cousin.
d) No relation at all.

ANS:- a, Uncle.

In a similar way questions based on relations, cost Etc were asked.

Module 3: Technical questions (duration 15 min):

It consists of 15 questions where some are web based, html, protocols Etc.
For this section going through COMPUTER NETWORKS subject will be helpful to a great extent.

Module 4: Test on Analysis (duration 10 min):

This section is the most time consuming one. Here we are asked to Rate certain sites along with an explanation. The images of these sites are also provided to us for a clear view and better understanding.

The completion of this section (on time) is entirely based on your typing speed and at the same time you have to be good at assessing.

Wishing you all luck.
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Google Interview Questions Part - 1

Google Interview   Questions Part - 1     

         This is a list of interview puzzles used at     Google.   
  
You have to get from point A to point B. You don?t know if you can get     there. What would you do?Imagine you have a closet full of shirts. It?svery hard to find a     shirt. So what can you do to organize your shirts for easy retrieval?What method would you use to look up a word in a dictionary?   
    Every man in a village of 100 married couples has cheated on his wife.     Every wife in the village instantly knows when a man other than herhusband     has cheated, but does not know when her own husband has. The village has a     law that does not allow foradultery.Anywife who can prove thather     husband is unfaithful must kill him that very day. The women of the village     would neverdisobeythislaw.One day, the queen of the village visits and     announce that at least one husband has been unfaithful. What happens?You have eight balls all of the same size. 7 of them weigh the same, and     one of them weighs slightly more. How can you fine the ball that is heavier     by using a balance and only two weighings?How do youcutarectangular cake into two equal pieces when someone has     already taken a rectangular piece from it? The removed piece an be any size     or at any place in the cake. You are only allowed one straight cut.
  
    How many piano tuners are there in the entire world?
  
         What gives you joy?
        
    Mike has $20 more than Todd. How much does each have given that combined     they have $21 between them. You can?t use fractions in the answer. Hint:     This is a trick question, pay close attention to the condition)
  
         How many times a day a clock?s hands overlap?
        
    Two MIT math graduates bump into each other. They hadn?t seen each     other in over 20 years.
  
    The first grad says to the second: ?how have you been??
  
         Second: ?Great! I got married and I have three daughters now?
  
         First:  ?Really? how old are they??
  
         Second:  ?Well, the product of their ages is 72, and the sum of their ages     is the same as the number on that building over there..?
  
         First: ?Right, ok.. oh wait.. I still don?t know?
  
         second: ?Oh sorry, the oldest one just started to play the piano?
  
         First: ?Wonderful! my oldest is the same age!?
  
 Problem: How old are the     daughters?
  
    If you look at a clock and the time is 3:15, what is the angle between     the hour and the minute hands? (The answer to this is not zero!)
    Four people need to cross a rickety rope bridge to get back to their camp     at night. Unfortunately, they only have one flashlight and it only has     enough light left for seventeen minutes. The bridge is too dangerous to     cross without a flashlight, and it?s only strong enough to support two     people at any given time. Each of the campers walks at a different speed.     One can cross the bridge in 1 minute, another in 2 minutes, the third in 5     minutes, and the slow poke takes 10 minutes to cross.  How do the campers     make it across in 17 minutes?
  
         If the probability of observing a car in 30 minutes on a highway is 0.95,     what is the probability of observing a car in 10 minutes (assuming constant     default probability)?
        
         In a country in which people only want boys, every family continues to     have children until they have a boy. if they have a girl, they have another     child. if they have a boy, they stop. what is the proportion of boys to     girls in the country?
  
    You have an empty room, and a group of people waiting outside the room.     At each step, you may either get one person into the room, or get one out.     Can you make subsequent steps, so that every possible combination of people     is achieved exactly once?
            
     Google interview questions         
The rectangle puzzle has a special case which does allow for an answer.     If the rectangular removed piece is smaller than the cake, then the solution     is to make a cut which joins the centre of the cake with the centre of the     removed piece (if these centres are the same point, then any cut through     this one point). However, if the removed piece is the whole cake, then there     is no possible cut, since there is no cake. I wonder how many people figured     this out (and I include the people who made up the question).
        
The last question about putting people in a room is the only one related     to anything at Google. The solution is simply the Gray code, which is     actually something of mild interest in Computer Science, and whose knowledge     might actually be useful to future work at a computer company. The other     questions are either silly, trivial if you know some math, or just wrong.
        
the 8 balls question answer is
    1)take any 7balls from 8 and keep remaning aside
    2)take any 6balls from that 7 keep remaing aside
    NOW
    CASE:1)
    weigh:1)3 and 3 of that 6 if equal then
    weigh:2)that 1 and 1 from remaing finish.
  
CASE:2)
    weigh:1)same 3 and 3 of that 6 if not equal
    weigh:2) 1 and 1 of that odd 3 finish
        
The ball question is silly because the algorithm works for up to 9 balls.     In general, you can find the heavier ball in N weighings if there are at     most 3^N balls, so using a non power of 3 misses the point. The general     algorithm for 3^N balls is:
    Take 2 groups of 3^(N-1) balls. If they weigh the same, then the ball is     in the 3rd group, and you can find the ball in a further N-1 steps by     recursion. Otherwise, the ball is in the heavier group, and you can again     find it in N-1 further steps by recursion.
    The adjustment for non powers of 3 is clear.
    This is probably the easiest coin problem. The harder ones don?t tell     you if the coin is heavier or lighter.
        
You can also outwit the examiner in the clock quesiton. Normally the     answer would be 22, but that is assuming that there are only hour and minute     hands. However, you can outwit the examiner by making the formally correct     statement ?most clocks have a second hand? and just wait there until he     figures it out. Since this would obviously guarantee you wouldn?t get the     job, I?m wondering if the real point of these questions is to make sure     that you aren?t smarter than the people who made them up.
        
Anyone felt dumber reading Ilan?s responses?
    On the rectangular cake, don?t cut it from up to down. Cut across at     mid-height.
    The point of asking ?8″ balls is to lead people to think to weigh     4 with 4, 2 with 2, 1 with 1, etc. Weighing ?9″ balls actually make     the question easier.
    On the married couples question, use induction and start with the village     having only 1 couple, then 2, and so on. Think in terms if you were the     wife, and you cheated with someone?s husband, how would you deduce if your     husband cheated and whether or not the other wife can deduce.
        
If you look at a clock and the time is 3:15, what is the angle between     the hour and the minute hands?
    - Degrees per clock cycle or a circle: 360
    - Degrees per clock cycle Ticks: 360 / 60 (total minute ticks in a clock) =     6 degrees
    - Ticks between two hour digits: 5
    - Minute Hand Ticks per Hour Hand Movement: 60/5 = 12
    Using above data we can calculate the exact clock hands position &     angle for 3:15 Time i.e.
    - Minute Hand position will be: 3
    - Change in Hour Hand position will be: (5/12) * 15 = 1.25 (exact ticks out     of 5 hour ticks between two hour digits & this is also an exact ticks     difference from minute hand)
    - So, ar there is (360/60) 6 degrees difference between two clock ticks     hence thers is 1.25 * 6 = 7.50 exact degrees difference between minute &     hour hands in 3:15 clock time :)
        
The answer to the bridge crossing questions:
    I will use following terms.
    camper1 - camper who can cross the bridge in 1 minute
    camper2 - camper who can cross the bridge in 2 minute
    camper5 - camper who can cross the bridge in 5 minute
    camper10 - camper who can cross the bridge in 10 minute
    1. camper1 and camper2 crosses (2 min)
    2. camper1 gets back (1 min)
    3. camper5 and camper10 crosses (10 min)
    4. camper2 gets back (2 min)
    5. camper1 and camper2 crosses (2 min)
    Total 17 min.
        
To     CSharp?s question:
    ?If you look at a clock and the time is 3:15, what is the angle between     the hour and the minute hands??
    The way I thought it was (ends in same result as urs):
    The answer is that the hour hand moves 360 degrees in 12 hour. That is 30     degrees each hour - 7.5 degrees each quarter.
    Therefore the difference     between the hands at 3 and warter is 7.5 degrees !
        
MIT Math Graduates Problem:-We know that 72?s factor are 2*2*2*3*3.Now     we need to calculate all possible combinations of ages from those     factors.The Combinations will be:-(2,4,9) and (2,6,6) and (2,3,12) and     (3,3,8) and (3,6,4).For every combination the sum of ages will be (15) and     (14) and (17) and (14) and (13) respectively.14 is the only digit which     comes twice so that is the digit which is written on building that?s why     first graduate couldn?t find out their correct ages.So possibly the ages     should be (2,6,6) or (3,3,8).Now second graduate says that his oldest     daughter just learned piano so this statement indicate that his oldest     daughter is not twin so surely there ages will be 3 and 3 and 8.
        
The Restangular Cake solution:
    Whatever be the shape and size of the cut piece.
    Just cut the cake horizontally from mid of the height.
    thats all!
        
To explain the cake solution:
    1) cutting a whole cake in half, in one strait cut, requires going from     one side, through the center of the cake, to the other side (we can chose     any angle we like).
    2) cutting the empty part in half , using one strait cut, requires going     from one side of the empty part, through the center of the empty part, to     the other side of the empty part.
    - The solution requires both cutting the whole cake in half, and cutting     the empty section in half, so we combine (1) and (2) to one striat cut     through both centers.
    As explained by Ilan.
        
How many times a day a clock?s hands overlap?
    Only 11 times. Overlap exists on or after every hour except after     11′o clock.
    Srikanth Bethi
        
How many times a day a clock?s hands overlap?
    Above answer is incomplete?.in a it completes 2 rounds?in the round     it gets 11 times and in the second round it gets only 10 times?
    so the total is 21 times in a day
        
What gives you joy?
    Word ?YOU? is having letters ?Y? & ?O? and it requires     letter ?J? to make ?JOY?. So the answer is ?J?.
        
Another way of looking at the 3:15 clock problem:
    Normally hour hand moves 1/12 of clock each hour.
    For 15 mins, it?s 1/4 of that then, or 1/48.
    Then 360 degrees / 48 = 7.5 degrees.
    Same answer, of course.
        
For the $20 trick question, i think i just figured it out.
    M = 20 + T
    M + T = 21
    Substitute M: 20 + 2T = 21
    T = 0.5
    So, Todd has $0.50 and Mike has $20.50.
    Oh, and i didn?t use fractions in my answer.
    I used decimals.
        
probability of watching a car is .95 in 30 min
    it means probability of watching a car is 95% in 30 min
    probability of watching a car per minute is 95/30=1.9%
    probability of watching a car in 10 minute is 1.9* 10=19%
        
To Vimal     Garg,
    Your answer to the three girls? age is right, but you can?t just     verifying 72?s factor which is 2*2*2*3*3, because it is possible that the     youngest daughter?s age is 1, for example: 1, 6, 12.
    The point to the question is that, there must be several combinations result     in the same summary. Like 2+6+6 = 3+3+8 = 14. And there could be only one     who has the oldest age, that is 8
        
To gaurav     khatwani,
    your math is wrong in more than one spot.
    You can?t merely say probability of seeing a car in one minute is x and     therefore in 10 minutes its 10*x. Probabilities don?t add up like that.
    Think of tossing a quarter. The probability of seeing a heads in 2 flips     is 3/4 not 1/2 + 1/2.
    Solution (I think) is the probability of not seeing a car in 30 minutes     is 05%.
    If the probability of not seeing a car in 10 minutes is x. then for each     additional 10 minutes we multiply by x. so x^3 = .05
    So the probability of seeing a car in 10 minutes is thus 1 - cuberoot(.05)
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Google Interview Questions Part - 2

Google Interview   Questions Part - 2
Google interview questions
      
answer to boy and country question:
         say there are 100 families, that means there will be exactly 100 boys.     Lets figure out how many girls.
    50 families will have a girl on their first try,
    25 will have a girl on their second try
    12.5 on third and so on.
    so 1/2 of the population has at least 1 girl, 1/4 has at least 2 and so     on.
    this reduces to avg # of girls per family = 1/2 + 1/4 + 1/8? = 1
    so the proportion is 1 to 1
        
FWIW I interviewed there 11 times and didn?t get asked any of these.     Indeed, nothing like these. These are just puzzles. The questions I got     asked were arguably harder, but certainly more directly related to     engineering and computer science.
        
Query:     How do you cut a rectangular cake into two equal pieces when someone has     already taken a rectangular piece from it? The removed piece an be any size     or at any place in the cake. You are only allowed one straight cut.Soln. Proposed:
    Cake is a three dimentional thing. Irrespective of the size of a rectangular     piece cut from it, if we cut the cake horizontally from the middle of its     height, it?ll be cut in two equal halves.
        
the answer to the clock question is actually 23
    the first round starts at midnight when both hands are on 12 overlapping,     then an overlap occurs after each hour before noon, so, this is 11 overlaps,     + 1 at noon, + 11 more on the second round, making it 23 overlaps per day,     and the 24th one will be actually the first overlap of the next day,done
        
Cake:
    Start from a easy one. A straight line passing through the center of a     rectangle will cut the rectangle into two halves with same area.
    Now the problem. A line passing through both center will cut the cake into     tow halves with same area.
         Car:
    qbaler is correct I think. but i can not find what?s wrong with following     calculation.
    If the possibility of seeing 1 car in 10 min is p, then:
    1) chance of seeing 1 car in the first 10 min = p*(1-p)^2
    2) .. = (1-p)*p*(1-p)
    3)so, the chance of seeing 1 car in 30 min is:
    3*p*(1-p)^2 = 0.95
    => p = 1.465
        
guys
    the answer to the car question is
    cuberoot 95/ cuberoot 100
    the answer is easy.
    imagine that you roll a dice. what is the possibility to have a 1? 1/6 right
    roll it twice.. it s 1/36
    so think that 30 minutes is three times 10 minutes.
    to 95/100 (95%) is a cube of three numbers.
    which gives the correct result as cuberoot 95/ cuberoot 100
        
The probability to have a 1 show up if you roll a 6 sided die is indeed     1/6. You could end up with (1), (2), (3), (4), (5), or (6), and only (1) is     a favorable outcome.
    With two dice, there are 36 possible outcomes. I won?t list them all,     but here are a few:
    (1,1), (1,2), (1,3), ?
    (2,1), (2,2), ?
    (3,1), ?
    There are several favorable outcomes where a 1 is present out of the 36     rolls. There are 6 ways for the first die to be any number while the second     die is a 1, and there are 6 ways for the second die to be any number while     the second die is 1. Having counted (1,1) twice, you end up with 11/36 as     the probability of having at least one 1 show up when you roll two dice.
    Unless you are asking for (1,1), then the probability is 1/36.
        
puttyshell:
    The question doesn?t ask ?What is the probability of seeing 1 car in 10     minutes, and no cars in the other 20 minutes??
    Also, your final answer of p = 1.465 is not possible because that value     is greater than 1!
        
For the Mike and Todd problem, it says there is a tricky question. I got     a different angle of the problem.
    Let T have x, then M has x+20.
    They both have to give sth so they have 21 between them.
    So x should be 1, so that M gives 20 and T gives 1 to make 21 between     them.
        
For the boy girl ratio problem, the number of girls is a taylors series:
    probability of having a boy in the first try is 0.5
    and the second is 0.25 etc. assuming no kids die then
    the number of girls would follow:
    x * (0.5 + 0.25 + 0.125 + ?) or Sum(1/(2^i), i=1..infinity) which is equal     to 2.
    So on average there should be 1 boy to 2 girls.
        
for the cake problem?.      if the cut is made horizontally in the middle
    of the depth of the cake it will be 2 equal pieces, no matter what the
    size or shape or place of the cut?
    And for the clock? answer is 22?this can be found easily , as each     overlap of the 2 hands occur at 12/11th of an hour?
        
For the searching the words in dictionary.. I feel the binary search as     the best method. As the search will be reduced to half after each iteration.
        
For the cake problem. As the original cake and removed piece are     rectangles. If you think these in 3dimensional view. Any line passing throug     their centroid( I mean center of gravity) will be the single straight cut.     If you cut in any other ways you can be proved false with some case.
        
qbaler,     you?re right that 1/2 + 1/4 + 1/8? = 1. however, the chance of having a     boy is still 1/2. So the proportion is 1 to 1/2 (or 2 to 1)
        
Assuming it?s an analogue clock, the clock is probably built with one     skrew in the middle which hold the two hands in place. Since it is most     always one skrew for both hands, the two hands overlap in the middle all day     and night. So the answer is that the hands overlap all day and night.
        
Regarding the clock angle prob:
         Solution:-
    We need to identify two things:
    1. Angle movement per hour :- 360/12 = 30 degree
    3. Angle movement per minute corresponding to per hour :- 0.5 (1 hour = 30     degree; 60 minute = 30 degree; 1 minute = 30/60 = 0.5 degree)
    So, 15 minute movement will create angle of 7.5 degree (.5 * 15) between     hour and minute hand.
        
1. by colour
    2. buy some dictionary first
    3. nothing queen doesnt live in the city and her husband was unfaithful
    4. take 6 then take 2
    5. find the man with the missing piece and get it
    6. less then pianos
    7. joy is to read this and know some questions so u can talk to yourself you     are not dump
    8. $20 and $1
    9. dont understand my english poor, dont know when they achieve their mit     and the sentence with 72
    10. if its not 0 so its 360
    11. 1&2 then 1 come back then 5&10 then 2 come back then 1&2
    12. 0.95
    13. girls > boys cause they want boys
    14. hmm again my english poor dont understand the sentence
        
Maybe I am wrong, but I see people made the clock question over     complicated. The Way I see it is that for each hour the minute hand makes a     full circle, so for each hour they over lap only once and therefore for 12     hours its gonna be 12 times.
        
The boy girl problem is simple (once you get past the implicit assumption     that boys/girls are each born 50% of the time, which technically isn?t     exactly true).
    No matter what strategy people use, every time someone gets pregnant,     there is a 50/50 chance of boy/girl. The final ratio is 1:1.
    A better formed problem would be a room full of coin flippers. If     everyone flipped until they got a Head, in the end, you would expect a total     of 50% heads and 50% tails. Figure out a different answer, then take it to     Vegas and try to beat a roullette wheel :)
        
Actually the ?8 ball? question is much more interesting when we do     not know that odd ball is lighter or heavier others. We will need one more     weighing though, but we can increase number of balls to 12.
        
ques: You have to get from point A to point B. You don?t know if you     can get there. What would you do?
  
Ans: I will start searching for Point B moving on a spiral path starting     from point B.
        
ques:      Imagine you have a closet full of shirts. It?s very hard to find a     shirt. So what can you do to organize your shirts for easy retrieval?
  
Ans. separate shirts on the basis of color and then arrange according to     company?s name in alphabetical order.
        
2. Imagine you have a closet full of shirts. It?s very hard to find a     shirt. So what can you do to organize your shirts for easy retrieval?
    I would first ask myself what criteria I normally use when looking for a     shirt. I would then sort sort them according to those criteria, pretty much     like a DBA does when indexing tables to optimize them most frequent queries.
        
Dingo, you are right. I was actually thinking the flawed way, until I     tried to right a Python script to simulate the problem (I?m a good     programmer, but terrible at calculus). You don?t even have to run to see     that the result will always be 0.5 (assuming random() is really random :)
    import random
    boysCount = 0
    girlsCount = 0
    for a in xrange(10000000):
    isGirl = random.random()
    while isGirl
        
Q: You have an empty room, and a group of people waiting outside the     room. At each step, you may either get one person into the room, or get one     out. Can you make subsequent steps, so that every possible combination of     people is achieved exactly once?
         A: Yes.
    See if you notice the pattern (0 = outside, 1 = inside):
    000000
    000001
    000011
    000010
    000110
    000111
    000101
    000100
    001100
    001101
    001111
    001011
    001001
    001000
    011000
    011100
    011110
    011111
    010111
    010011
    010001
    010000
    This pattern will cover every possible combination and can be repeated     for any number of bits (people). Other valid patterns may exist.
        
Q: You have to get from point A to point B. You don?t know if you can     get there. What would you do?
         A:
    I?d start by googling ?A B?, gathering as much information as     possible;
    Then, I?d try to talk to someone in the team knowledgeable on those     points;
    Next, I?d go back to my lead and make sure I?ve understood what A and B     are;
    Hopefully, this should give me enough information start the journey;
        
Clock hands will overlap 22 times (All times approximate):
    00:00, 01:05, 02:10, 03:15, 04:20, 05:25, 06:30, 07:35, 08:40, 09:45, 10:50,
    12:00, 13:05, 14:10, 15:15, 16:20, 17:25, 18:30, 19:35, 20:40, 21:45, 22:50
        
Q: How many piano tuners are there in the entire world?
         Assuming:
         * World population 6 billion
    * One in 10000 people own a piano
    * One tuner will tune, on average, 2 pianos a day
    * A piano needs tuning once every year
    There are 600000 pianos;
    They will require 600000 tuning every year
    One single tuner can tune 520 pianos a year (2 tunes x 260 week days in the     year)
    Approximately 1153 piano tuners are required.
    In questions like this, they are not really interested in the answer you     give, but how did you get to it. Stating your assumptions as clearly as     possible helps. Also, you may want to get to your answer using two or     rationales. In this case, you may want to guess the number of pianos by the     number of house holds in the world and the ratio of those with enough money     to own a piano, etc.
        
Clock hands - 24 times per day. For those of you who stated that at the     end of the day (midnight), it is actually the next day - if you use this     assumption, then you must count that as the first time they cross on that     day. You can simplify the question by asking ?How many revolutions does     the minute hand make in a day?? 24
    Unfaithful husband - the only woman who isn?t aware of the infidelity     immediatelly kills her husband (everyone else already knows he did it,     including the Queen - how much more proof do you need?).
        
If you look at a clock and the time is 3:15, what is the angle between     the hour and the minute hands? (The answer to this is not zero!)
    360/(12*4)= 7.5 degree is the angle ?where 4 comes from (60/15)
        
The cake: It?s not possible, in practical terms, to cut any cake     equally. Cutting it horizontally ignores the roundness at the top of the     cake, to say nothing of the extra frosting on top, or who gets the rose     decoration. Even if one rules those things out, there will always be     something to quarrel about, no matter how the cake is divided. That?s why     in a case like this, you ask one recipient to cut it, and the other     recipient to have first choice re which piece he wants. Trust me, I have     twin boys.
        
Two MIT math graduates bump into each other. They hadn?t seen each     other in over 20 years.
    The first grad says to the second: ?how have you been??
    Second: ?Great! I got married and I have three daughters now?
    First: ?Really? how old are they??
    Second: ?Well, the product of their ages is 72, and the sum of their ages     is the same as the number on that building over there..?
    First: ?Right, ok.. oh wait.. I still don?t know?
    second: ?Oh sorry, the oldest one just started to play the piano?
    First: ?Wonderful! my oldest is the same age!? Problem: How old are the     daughters?
    ? The answer: Unknown.
    The solution makes false assumptions:
    1.) The guy knew that two possible combinations had the sum 14
    2.) The guy could see the building number
    3.) Two children cannot be the same age.
    Key #3 is the most important. It is possible to have two six year olds     and a two year old. Twins. With twins, there is ALWAYS an older child. So,     it is perfectly legit to say that you have two six year olds, one two year     old, and the oldest began playing piano.
        
Jay Jay? What about 11:55 and 23:55?
    Cake? Horizontal cut answers assume the rectangle removed is the same     height as the cake.
    As pointed out by Jay Jay, if I asked you any questions like these it is     your thinking process that I care about. Are you easily discouraged by a     tough situation? Do you find negatives or solutions? Can you venture a     solution even if it might be wrong?
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Google Placement Paper & Pattern

Google Placement Paper and Sample Paper

GLAT (Google Labs Aptitude Test)

1. Solve this cryptic equation, realizing of course that values for M and E could be interchanged. No leading zeros are allowed.

WWWDOT - GOOGLE = DOTCOM

This can be solved through systematic application of logic. For example, cannot be equal to 0, since . That would make , but , which is not possible.

Here is a slow brute-force method of solution that takes a few minutes on a relatively fast machine:

This gives the two solutions

777589 - 188106 == 589483
777589 - 188103 == 589486

Here is another solution using Mathematica's Reduce command:

A faster (but slightly more obscure) piece of code is the following:

Faster still using the same approach (and requiring ~300 MB of memory):

Even faster using the same approach (that does not exclude leading zeros in the solution, but that can easily be weeded out at the end):

Here is an independent solution method that uses branch-and-prune techniques:

And the winner for overall fastest:

2. Write a haiku describing possible methods for predicting search traffic seasonality.

MathWorld's search engine
seemed slowed this May. Undergrads
prepping for finals.

3.

1
1 1
2 1
1 2 1 1
1 1 1 2 2 1
What's the next line?

312211. This is the "look and say" sequence in which each term after the first describes the previous term: one 1 (11); two 1s (21); one 2 and one 1 (1211); one 1, one 2, and two 1's (111221); and so on. See the look and say sequence entry on MathWorld for a complete write-up and the algebraic form of a fascinating related quantity known as Conway's constant.

4. You are in a maze of twisty little passages, all alike. There is a dusty laptop here with a weak wireless connection. There are dull, lifeless gnomes strolling around. What dost thou do?

A) Wander aimlessly, bumping into obstacles until you are eaten by a grue.
B) Use the laptop as a digging device to tunnel to the next level.
C) Play MPoRPG until the battery dies along with your hopes.
D) Use the computer to map the nodes of the maze and discover an exit path.
E) Email your resume to Google, tell the lead gnome you quit and find yourself in whole different world [sic].

In general, make a state diagram . However, this method would not work in certain pathological cases such as, say, a fractal maze. For an example of this and commentary, see Ed Pegg's column about state diagrams and mazes .

5. What's broken with Unix?

Their reproductive capabilities.

How would you fix it?

[This exercise is left to the reader.]

6. On your first day at Google, you discover that your cubicle mate wrote the textbook you used as a primary resource in your first year of graduate school. Do you:

A) Fawn obsequiously and ask if you can have an autograph.
B) Sit perfectly still and use only soft keystrokes to avoid disturbing her concentration
C) Leave her daily offerings of granola and English toffee from the food bins.
D) Quote your favorite formula from the textbook and explain how it's now your mantra.
E) Show her how example 17b could have been solved with 34 fewer lines of code.

[This exercise is left to the reader.]

7. Which of the following expresses Google's over-arching philosophy?

A) "I'm feeling lucky"
B) "Don't be evil"
C) "Oh, I already fixed that"
D) "You should never be more than 50 feet from food"
E) All of the above

[This exercise is left to the reader.]

8. How many different ways can you color an icosahedron with one of three colors on each face?

For an asymmetric 20-sided solid, there are possible 3-colorings . For a symmetric 20-sided object, the Polya enumeration theorem can be used to obtain the number of distinct colorings. Here is a concise Mathematica implementation:

What colors would you choose?

[This exercise is left to the reader.]

9. This space left intentionally blank. Please fill it with something that improves upon emptiness.

For nearly 10,000 images of mathematical functions, see The Wolfram Functions Site visualization gallery .

10. On an infinite, two-dimensional, rectangular lattice of 1-ohm resistors, what is the resistance between two nodes that are a knight's move away?

This problem is discussed in J. Cserti's 1999 arXiv preprint . It is also discussed in The Mathematica GuideBook for Symbolics, the forthcoming fourth volume in Michael Trott's GuideBook series, the first two of which were published just last week by Springer-Verlag. The contents for all four GuideBooks, including the two not yet published, are available on the DVD distributed with the first two GuideBooks.

11. It's 2PM on a sunny Sunday afternoon in the Bay Area. You're minutes from the Pacific Ocean, redwood forest hiking trails and world class cultural attractions. What do you do?

[This exercise is left to the reader.]

12. In your opinion, what is the most beautiful math equation ever derived?

There are obviously many candidates. The following list gives ten of the authors' favorites:

1. Archimedes' recurrence formula : , , ,
2. Euler formula :
3. Euler-Mascheroni constant :
4. Riemann hypothesis: and implies
5. Gaussian integral :
6. Ramanujan's prime product formula:
7. Zeta-regularized product :
8. Mandelbrot set recursion:
9. BBP formula :
10. Cauchy integral formula:

An excellent paper discussing the most beautiful equations in physics is Daniel Z. Freedman's " Some beautiful equations of mathematical physics ." Note that the physics view on beauty in equations is less uniform than the mathematical one. To quote the not-necessarily-standard view of theoretical physicist P.A.M. Dirac, "It is more important to have beauty in one's equations than to have them fit experiment."

13. Which of the following is NOT an actual interest group formed by Google employees?

A. Women's basketball
B. Buffy fans
C. Cricketeers
D. Nobel winners
E. Wine club

[This exercise is left to the reader.]

14. What will be the next great improvement in search technology?

Semantic searching of mathematical formulas. See http://functions.wolfram.com/About/ourvision.html for work currently underway at Wolfram Research that will be made available in the near future.

15. What is the optimal size of a project team, above which additional members do not contribute productivity equivalent to the percentage increase in the staff size?

A) 1
B) 3
C) 5
D) 11
E) 24

[This exercise is left to the reader.]

16. Given a triangle ABC, how would you use only a compass and straight edge to find a point P such that triangles ABP, ACP and BCP have equal perimeters? (Assume that ABC is constructed so that a solution does exist.)

This is the isoperimetric point , which is at the center of the larger Soddy circle. It is related to Apollonius' problem . The three tangent circles are easy to construct: The circle around has diameter , which gives the other two circles. A summary of compass and straightedge constructions for the outer Soddy circle can be found in " Apollonius' Problem: A Study of Solutions and Their Connections" by David Gisch and Jason M. Ribando.

17. Consider a function which, for a given whole number n, returns the number of ones required when writing out all numbers between 0 and n.
 For example, f(13)=6. Notice that f(1)=1. What is the next largest n such that f(n)=n?

The following Mathematica code computes the difference between [the cumulative number of 1s in the positive integers up to n] and [the value of n itself] as n ranges from 1 to 500,000:

The solution to the problem is then the first position greater than the first at which data equals 0:

which are the first few terms of sequence A014778 in the On-Line Encyclopedia of Integer Sequences.

Checking by hand confirms that the numbers from 1 to 199981 contain a total of 199981 1s:

18. What is the coolest hack you've ever written?

While there is no "correct" answer, a nice hack for solving the first problem in the SIAM hundred-dollar, hundred-digit challenge can be achieved by converting the limit into the strongly divergent series:

and then using Mathematica's numerical function SequenceLimit to trivially get the correct answer (to six digits),

You must tweak parameters a bit or write your own sequence limit to get all 10 digits.

[Other hacks are left to the reader.]

19. 'Tis known in refined company, that choosing K things out of N can be done in ways as many as choosing N minus K from N: I pick K, you the remaining.

This simply states the binomial coefficient identity .

Find though a cooler bijection, where you show a knack uncanny, of making your choices contain all K of mine. Oh, for pedantry: let K be no more than half N.

'Tis more problematic to disentangle semantic meaning precise from the this paragraph of verbiage peculiar.

20. What number comes next in the sequence: 10, 9, 60, 90, 70, 66, ?

A) 96
B) 100
C) Either of the above
D) None of the above

This can be looked up and found to be sequence A052196 in the On-Line Encyclopedia of Integer Sequences, which gives the largest positive integer whose English name has n letters. For example, the first few terms are ten, nine, sixty, ninety, seventy, sixty-six, ninety-six, ?. A more correct sequence might be ten, nine, sixty, googol, seventy, sixty-six, ninety-six, googolplex. And also note, incidentally, that the correct spelling of the mathematical term " googol" differs from the name of the company that made up this aptitude test.

The first few can be computed using the NumberName function in Eric Weisstein's MathWorld packages:

A mathematical solution could also be found by fitting a Lagrange interpolating polynomial to the six known terms and extrapolating:

21. In 29 words or fewer, describe what you would strive to accomplish if you worked at Google Labs.

[This exercise is left to the reader.]
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Google Placement Paper and Sample Paper
Paper : Google Placement Paper and Sample Paper

Google Placement Paper and Sample Paper
This Google has conducted recruitment process in our collage.The criteria was first 30% topper in the class.So around 40 student has attended the test & only 4 could clear the test. Test consist of 15 question based on c,c++,and data structure.and two c programs. So i am listing some of the question as i remembered.

1. Solve this cryptic equation, realizing of course that values for M and E could be interchanged. No leading zeros are allowed.
This can be solved through systematic application of logic. For example, cannot be equal to 0, since . That would make , but , which is not possible. Here is a slow brute-force method of solution that takes a few minutes on a relatively fast machine:
This gives the two solutions :
777589 - 188106 == 589483
777589 - 188103 == 589486

Here is another solution using Mathematica's Reduce command:
A faster (but slightly more obscure) piece of code is the following:
Faster still using the same approach (and requiring ~300 MB of memory):
Even faster using the same approach (that does not exclude leading zeros in the solution, but that can easily be weeded out at the end):
Here is an independent solution method that uses branch-and-prune techniques: And the winner for overall fastest:


2. Write a haiku describing possible methods for predicting search traffic seasonality. MathWorld's search engine seemed slowed this May. Undergrads prepping for finals.


3.
 1
1 1
2 1
1 2 1 1
1 1 1 2 2 1

What's the next line?
312211.

This is the "look and say" sequence in which each term after the first describes the previous term: one 1 (11); two 1s (21); one 2 and one 1 (1211); one 1, one 2, and two 1's (111221); and so on. See the look and say sequence entry on MathWorld for a complete write-up and the algebraic form of a fascinating related quantity known as Conway's constant.


4. You are in a maze of twisty little passages, all alike. There is a dusty laptop here with a weak wireless connection. There are dull, lifeless gnomes strolling around. What dost thou do?
A) Wander aimlessly, bumping into obstacles until you are eaten by a grue.
B) Use the laptop as a digging device to tunnel to the next level.
C) Play MPoRPG until the battery dies along with your hopes.
D) Use the computer to map the nodes of the maze and discover an exit path.
E) Email your resume to Google, tell the lead gnome you quit and find yourself in whole different world [sic].
In general, make a state diagram . However, this method would not work in certain pathological cases such as, say, a fractal maze. For an example of this and commentary, see Ed Pegg's column about state diagrams and mazes .


5. What's broken with Unix?
Their reproductive capabilities.
How would you fix it?



6. On your first day at Google, you discover that your cubicle mate wrote the textbook you used as a primary resource in your first year of graduate school. Do you:
A) Fawn obsequiously and ask if you can have an autograph.
B) Sit perfectly still and use only soft keystrokes to avoid disturbing her concentration
C) Leave her daily offerings of granola and English toffee from the food bins.
D) Quote your favorite formula from the textbook and explain how it's now your mantra.
E) Show her how example 17b could have been solved with 34 fewer lines of code.



7. Which of the following expresses Google's
over-arching philosophy?
A) "I'm feeling lucky"
B) "Don't be evil"
C) "Oh, I already fixed that"
D) "You should never be more than 50 feet from food"
E) All of the above

8. How many different ways can you color an icosahedron with one of three colors on each face?
For an asymmetric 20-sided solid, there are possible 3-colorings . For a symmetric 20-sided object, the Polya enumeration theorem can be used to obtain the number of distinct colorings. Here is a concise Mathematica implementation: What colors would you choose?

9. This space left intentionally blank. Please fill it with something that improves upon emptiness.
For nearly 10,000 images of mathematical functions, see The Wolfram Functions Site visualization gallery .

10. On an infinite, two-dimensional, rectangular lattice of 1-ohm resistors, what is the resistance between two nodes that are a knight's move away?

This problem is discussed in J. Cserti's 1999 arXiv preprint . It is also discussed in The Mathematica GuideBook for Symbolics, the forthcoming fourth volume in Michael Trott's GuideBook series, the first two of which were published just last week by Springer-Verlag. The contents for all four GuideBooks, including the two not yet published, are available on the DVD distributed with the first two GuideBooks. 11. It's 2PM on a sunny Sunday afternoon in the Bay Area. You're minutes from the Pacific Ocean, redwood forest hiking trails and world class cultural attractions. What do you do?


12. In your opinion, what is the most beautiful math equation ever derived? There are obviously many candidates. The following list gives ten of the authors'
favorites:
1. Archimedes' recurrence formula : , , ,
2. Euler formula :
3. Euler-Mascheroni constant :
4. Riemann hypothesis: and implies
5. Gaussian integral :
6. Ramanujan's prime product formula:
7. Zeta-regularized product :
8. Mandelbrot set recursion:
9. BBP formula :
10. Cauchy integral formula:

An excellent paper discussing the most beautiful equations in physics is Daniel Z. Freedman's " Some beautiful equations of mathematical physics ." Note that the physics view on beauty in equations is less uniform than the mathematical one. To quote the notnecessarily- standard view of theoretical physicist P.A.M. Dirac, "It is more important to have beauty in one's equations than to have them fit experiment."

13. Which of the following is NOT an actual interest group formed by Google employees?
A. Women's basketball
B. Buffy fans
C. Cricketeers
D. Nobel winners
E. Wine club

14. What will be the next great improvement in search technology? Semantic searching of mathematical formulas.
See : http: // functions.wolfram.com/About/ourvision.html for work currently underway at Wolfram Research that will be made available in the near future.

15. What is the optimal size of a project team, above which additional members do not contribute productivity equivalent to the percentage increase in the staff size?
A) 1
B) 3
C) 5
D) 11
E) 24

16. Given a triangle ABC, how would you use only a compass and straight edge to find a point P such that triangles ABP, ACP and BCP have equal perimeters? (Assume that ABC is constructed so that a solution does exist.) This is the isoperimetric point , which is at the center of the larger Soddy circle. It is related to Apollonius' problem . The three tangent circles are easy to construct: The circle around has diameter , which gives the other two circles. A summary of compass and straightedge constructions for the outer Soddy circle can be found in " Apollonius' Problem: A Study of Solutions and Their Connections" by David Gisch and Jason M. Ribando.

17. Consider a function which, for a given whole number n, returns the number of ones required when writing out all numbers between 0 and n. For example, f(13)=6. Notice that
f(1)=1. What is the next largest n such that
f(n)=n?

Q1) What is the value of i after execution of the following program.
void main()
{
long l=1024;
int i=1;
while(l>=1)
{ l=l/2;
i=i+1;
}
}
a)8 b)11 c)10 d)100 ans:b


Q2) This question is based on the complexity ...

Q3)
s->AB
A->a
B->bbA
Which one is false for above grammer..

Some Tree were given & the question is to fine preorder traversal.

Q4) One c++ program,to find output of the program..

Q5) If the mean faliure hour is 10,000 and 20 is the mean repair hour.If the printer is used by 100 customer,then find the availability.
1)80% 2)90% 3)98% 4)99.8% 5)100%

Q6)One question on probability...

Q7)In a singly linked list if there is a pointer S on the first element and pointer L is on the last element.Then which operation will take more time based on the lenght of the list.
1)Adding element at the first.
2)adding element at the end of the list.
3)To exchange the fisrt 2 element.
4)Deleting the element from the end of the list.
ans:2 check it!

3 more question to fine the output of the program. and rest of the question was based on data structure, some condition where given and we have to conlude either y or n The second section was coding...
1)Write a fucntion to multiply 2 N*N matrix Write test cases for ur code.
2) S contains the set of positive integer.Find the largest number c such that c=a+b where a,b,c are distict number of the set.
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